判断一个网站和网页是否能打开

作者: Love02xp 日期: 2019-02-27 19:45:47 分类: 编程代码 标签: 代码, 编程, php 路径: C2.VC6.MFC/
[阅读原文]()

方法一：

<?php 
$web_url = 'http://192.168.88.1';
$ch = curl_init($web_url);  
curl_setopt($ch, CURLOPT_HEADER, 0);  
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);   
$contents = curl_exec($ch);
curl_close($ch);
if($contents === false){
    echo('打不开!');
}else{
    echo('能打开!');
} 
?>

方法二：

<?php
//如果显示为200则正常，如果显示其它值表示不正常；$timeout后面的3是设置超时秒数。
 function httpcode($url){
  $ch = curl_init();
  $timeout = 3;
  curl_setopt($ch,CURLOPT_FOLLOWLOCATION,1);
  curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
  curl_setopt($ch, CURLOPT_HEADER, 1);
  curl_setopt ($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
  curl_setopt($ch,CURLOPT_URL,$url);
  curl_exec($ch);
  return $httpcode = curl_getinfo($ch,CURLINFO_HTTP_CODE);
  curl_close($ch);
}
echo "111：".httpcode('http://192.168.88.1');
?>